Asked by saba
at a ball game consider a baseball of mass m=0.15 that falls directly downward at a speed v=40m/s into the hands of a fan. what impulseft must be supplied to bring the ball to rest? if the ball is stopped in 0.3s, what is the average force of the ball on the catchers hand?
Answers
Answered by
MathMate
Impulse = change of momentum
= m(v0-v1)
Average force = change of momentum / time
= m(v0-v1)/0.3 N (assuming m=0.15 kg)
= m(v0-v1)
Average force = change of momentum / time
= m(v0-v1)/0.3 N (assuming m=0.15 kg)
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