Question

In the game Roulette, a ball spins on a circular wheel that is divided into 38 arcs of equal lenght, numbered 00, 0, 1, 2, ... , 35, 36. The number on the arc on which the ball stops is the outcome of one play of the game. The numbers are also colored as follows:
1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36 are red,
2, 4, 6, 8, 10, 11, 13, 15, 17, 20, 22, 24, 26, 28, 29, 31, 33, 35 are black,
0, 00 are green
Define the following events:
A:{ Outcome is an even number (0 and 00 are considered neither odd nor even) }
B:{ Outcome is a red number }
C:{ Outcome is a green number }
D:{ Outcome is a low number (1-18) }
Find the following probablilities (Keep at least 3 digits) :
(a) P(A) =
0.473

(c) P(A U B U C)= 18+18+2/38= 1
I'm getting c wrong

Answer 1

P(A) is right.

P(C) = 2/38 = .053

Only two choices are green. Why did you add 18 twice?

Answer 2

it says 0.053 is wrong