Question
In the game Roulette, a ball spins on a circular wheel that is divided into 38 arcs of equal lenght, numbered 00, 0, 1, 2, ... , 35, 36. The number on the arc on which the ball stops is the outcome of one play of the game. The numbers are also colored as follows:
1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36 are red,
2, 4, 6, 8, 10, 11, 13, 15, 17, 20, 22, 24, 26, 28, 29, 31, 33, 35 are black,
0, 00 are green
Define the following events:
A:{ Outcome is an even number (0 and 00 are considered neither odd nor even) }
B:{ Outcome is a red number }
C:{ Outcome is a green number }
D:{ Outcome is a low number (1-18) }
Find the following probablilities (Keep at least 3 digits) :
(a) P(A) =
0.473
(c) P(A U B U C)= 18+18+2/38= 1
I'm getting c wrong
1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36 are red,
2, 4, 6, 8, 10, 11, 13, 15, 17, 20, 22, 24, 26, 28, 29, 31, 33, 35 are black,
0, 00 are green
Define the following events:
A:{ Outcome is an even number (0 and 00 are considered neither odd nor even) }
B:{ Outcome is a red number }
C:{ Outcome is a green number }
D:{ Outcome is a low number (1-18) }
Find the following probablilities (Keep at least 3 digits) :
(a) P(A) =
0.473
(c) P(A U B U C)= 18+18+2/38= 1
I'm getting c wrong
Answers
PsyDAG
P(A) is right.
P(C) = 2/38 = .053
Only two choices are green. Why did you add 18 twice?
P(C) = 2/38 = .053
Only two choices are green. Why did you add 18 twice?
tom
it says 0.053 is wrong