Asked by Mark

Solve.

log(x^3)-log(2)=log(2x^2)
Answered by bobpursley
3logx-log2=2logx*log2
3logx-2logx log2=log2
logx(3-2log2)=log2
logx= log2/(3-2log2)

look up log2, and solve.
Answered by Mark
I don't think that is right
answer is x=4
not sure how
Answered by Reiny
how about this:

log(x^3)-log(2)=log(2x^2)
log [x^3/2] = log(2x^2)
x^3/2 = 2x^2
x^3 = 4x^2
x^3 - 4x^2 = 0
x^2(x-4) = 0
x = 0, not possible
or
x = 4
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