Asked by Donald Craven
A circuit is constructed with a 20.0-V power supply and two resistors in series: R1 = 4.00 ohms, and R2 = 2.00 ohms. What is the resulting current in the circuit?(1 point)
Responses
3.33 A
3.33 A
15.0 A
15.0 A
27.0 A
27.0 A
120.0 A
Responses
3.33 A
3.33 A
15.0 A
15.0 A
27.0 A
27.0 A
120.0 A
Answers
There are no human answers yet.
Answered by
GPT 3.5
To find the resulting current in the circuit, we can use Ohm's Law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance.
First, we need to find the total resistance in the circuit, which is the sum of the resistances in series: R_total = R1 + R2 = 4.00 ohms + 2.00 ohms = 6.00 ohms.
Then, we can use Ohm's Law to find the current: I = V/R_total = 20.0 V / 6.00 ohms = 3.33 A.
Therefore, the resulting current in the circuit is 3.33 A.
First, we need to find the total resistance in the circuit, which is the sum of the resistances in series: R_total = R1 + R2 = 4.00 ohms + 2.00 ohms = 6.00 ohms.
Then, we can use Ohm's Law to find the current: I = V/R_total = 20.0 V / 6.00 ohms = 3.33 A.
Therefore, the resulting current in the circuit is 3.33 A.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.