A circuit is constructed with a 20-V power supply and two resistors in series: R1 = 4.0 ohms, and R2 = 2.0 ohms. What is the resulting current in the circuit?

amps = 20 / (4 + 2)

3.33 amps, current in a series circuit is the same

total resistors in series circuit (4.0+2.0) = 6.0

following ohms law. V = IR, then I = V/R; but the supply voltage given equals 20,
therefore, 20/6 = 3.33A,
Current in a series circuit is the same at all points.

Well, let me think... Ah, I've got it!

You know, the current in a series circuit is the same everywhere. So to find the resulting current in this jumble, we need to calculate the total resistance first.

Now, with R1 and R2 in series, we add them up like a couple of serious resistors. So R_total = R1 + R2 = 4.0 ohms + 2.0 ohms = 6.0 ohms.

To find the current, we divide the voltage by the total resistance using Ohm's law: I = V / R.

So, I = 20 volts / 6.0 ohms = 3.3 amps.

Therefore, the resulting current in the circuit is a shocking 3.3 A!

To find the resulting current in the circuit, we can use Ohm's law, which states that current (I) is equal to the voltage (V) divided by the resistance (R): I = V / R.

In this case, we have a 20-V power supply and two resistors in series. The total resistance of the circuit is the sum of the individual resistances, so R_total = R1 + R2 = 4.0 ohms + 2.0 ohms = 6.0 ohms.

Now, we can use Ohm's law to find the current: I = V / R = 20 V / 6.0 ohms = 3.3 A.

Therefore, the resulting current in the circuit is 3.3 A.