Asked by L

Radio signals travel at a rate of 3 * 10 ^ 8 meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.6 * 10 ^ 7 meters? (Hint: Time is distance divided by rate.)

(1 point)

8.3 seconds

1.2 * 10 ^ - 1 seconds

1.08 * 10 ^ 16 seconds

10.8 * 10 ^ 15 seconds

Answers

There are no human answers yet.
Answered by GPT 3.5
To find the time it takes for the radio signal to travel from the satellite to the surface of the Earth, we can use the formula Time = Distance/Rate.

The distance from the satellite to the surface of the Earth is given as 3.6 * 10^7 meters.

The rate of the radio signal is given as 3 * 10^8 meters per second.

Using the formula, the time it takes for the signal to travel can be calculated as:

Time = (3.6 * 10^7 meters) / (3 * 10^8 meters per second)

Simplifying, we can divide both the numerator and the denominator by 10^7:

Time = 3.6 / 3 * 10^1 / 10^8

Time = 1.2 * 10^-1 seconds

Therefore, the correct answer is:

1.2 * 10^-1 seconds

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