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radio signals travel at a rate of 3x10^8 meters per second.How many seconds will it take for a radio signal to travel from a sa...Asked by L
Radio signals travel at a rate of 3 * 10 ^ 8 meters per second. How many seconds would it take for a radio signal to travel from a satellite to the surface of Earth if the satellite is orbiting at a height of 3.6 * 10 ^ 7 meters? (Hint: Time is distance divided by rate.)
(1 point)
8.3 seconds
1.2 * 10 ^ - 1 seconds
1.08 * 10 ^ 16 seconds
10.8 * 10 ^ 15 seconds
(1 point)
8.3 seconds
1.2 * 10 ^ - 1 seconds
1.08 * 10 ^ 16 seconds
10.8 * 10 ^ 15 seconds
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Answered by
GPT 3.5
To find the time it takes for the radio signal to travel from the satellite to the surface of the Earth, we can use the formula Time = Distance/Rate.
The distance from the satellite to the surface of the Earth is given as 3.6 * 10^7 meters.
The rate of the radio signal is given as 3 * 10^8 meters per second.
Using the formula, the time it takes for the signal to travel can be calculated as:
Time = (3.6 * 10^7 meters) / (3 * 10^8 meters per second)
Simplifying, we can divide both the numerator and the denominator by 10^7:
Time = 3.6 / 3 * 10^1 / 10^8
Time = 1.2 * 10^-1 seconds
Therefore, the correct answer is:
1.2 * 10^-1 seconds
The distance from the satellite to the surface of the Earth is given as 3.6 * 10^7 meters.
The rate of the radio signal is given as 3 * 10^8 meters per second.
Using the formula, the time it takes for the signal to travel can be calculated as:
Time = (3.6 * 10^7 meters) / (3 * 10^8 meters per second)
Simplifying, we can divide both the numerator and the denominator by 10^7:
Time = 3.6 / 3 * 10^1 / 10^8
Time = 1.2 * 10^-1 seconds
Therefore, the correct answer is:
1.2 * 10^-1 seconds
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