Asked by Bob

Two professional drag racers are speeding down a 1/4-mile track. If the lead driver is traveling 1.738 feet for every 1.670 feet that the trailing car travels, and if the trailing car is going 198 miles per hour, how fast in miles per hour is the lead car traveling?
Answered by MathMate
Use proportion:
1.67 ft : 1.738 ft = 198 mph : ?
Answered by Danny
200
Answered by Megan
Ratio of lead driver distance and trailing driver distance = StartFraction 1.716 Over 1.670 EndFraction
Speed of lead car = ratio times speed of trailing car = StartFraction 1.716 Over 1.670 EndFraction ⁢ times 197 ⁢ equals 202.4miles per hour