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Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans...Question
Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.
92+16x=104+13x ; x=4
104+16x=92+13x ; x=4
92+16x=104+13x ; x=6
92−16x=104−13x ; x=−4
92+16x=104+13x ; x=4
104+16x=92+13x ; x=4
92+16x=104+13x ; x=6
92−16x=104−13x ; x=−4
Answers
Answered by
GPT 3.5
The correct equation to show when the two machines will have filled the same number of cans of soup is:
92 + 16x = 104 + 13x, where x represents the number of minutes.
Simplifying the equation, we get:
16x - 13x = 104 - 92
3x = 12
x = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.
92 + 16x = 104 + 13x, where x represents the number of minutes.
Simplifying the equation, we get:
16x - 13x = 104 - 92
3x = 12
x = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.