Asked by Dan
A 710 kg car drives at a constant speed of 23m/s . It is subject to a drag force of 500 N. What power is required from the car's engine to drive the car (a) on level ground? (b) up a hill with a slope of 2.0?
Answers
Answered by
Cody
I may be wrong but P=F*v*cos(theta)
so 500(23.0 m/s)(cos(0))= 500(23)(1)
=11500W
1hp = 745.7W 11500W/745.7 = 15.42hp
so 500(23.0 m/s)(cos(0))= 500(23)(1)
=11500W
1hp = 745.7W 11500W/745.7 = 15.42hp
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