Question
A mass is thrown upwards with an initial velocity of 30m/s. A second mass is dropped from directly above, a height of 60m from the first mass 0.50s later. When do the masses meet and how hight is the point where they meet?
Answers
bobpursley
They travel a combined 60m
distanceup+distancedown=60
30t-1/2 g t^2+0-1/2 g (t-.5)^2=60
solve it.
distanceup+distancedown=60
30t-1/2 g t^2+0-1/2 g (t-.5)^2=60
solve it.
B
how am i supposed to solve it?