50*t+55*t=70
solve for t.
Jon left his house and headed toward Brandon's house at the same time Brandon headed toward Jon's house. Brandon traveled 50 mi/h and Jon traveled 55m/h. The distance between their homes is 70 miles. How long did they travel before they met?
Please help me wih this problem. Thank you.
2 answers
this is what i got im not sure if its right.
50t+55t=70
50t+55t=105t=70
70/105
t=1.5
50t+55t=70
50t+55t=105t=70
70/105
t=1.5
1 answer