Question
Jon left his house and headed toward Brandon's house at the same time Brandon headed toward Jon's house. Brandon traveled 50 mi/h and Jon traveled 55m/h. The distance between their homes is 70 miles. How long did they travel before they met?
Please help me wih this problem. Thank you.
Please help me wih this problem. Thank you.
Answers
bobpursley
50*t+55*t=70
solve for t.
solve for t.
Samantha
this is what i got im not sure if its right.
50t+55t=70
50t+55t=105t=70
70/105
t=1.5
50t+55t=70
50t+55t=105t=70
70/105
t=1.5