Asked by Samantha

Jon left his house and headed toward Brandon's house at the same time Brandon headed toward Jon's house. Brandon traveled 50 mi/h and Jon traveled 55m/h. The distance between their homes is 70 miles. How long did they travel before they met?
Please help me wih this problem. Thank you.
Answered by bobpursley
50*t+55*t=70
solve for t.
Answered by Samantha
this is what i got im not sure if its right.

50t+55t=70
50t+55t=105t=70
70/105
t=1.5
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