Asked by Samantha
                Jon left his house and headed toward Brandon's house at the same time Brandon headed toward Jon's house. Brandon traveled 50 mi/h and Jon traveled 55m/h. The distance between their homes is 70 miles. How long did they travel before they met?
Please help me wih this problem. Thank you.
            
        Please help me wih this problem. Thank you.
Answers
                    Answered by
            bobpursley
            
    50*t+55*t=70
solve for t.
    
solve for t.
                    Answered by
            Samantha
            
    this is what i got im not sure if its right.
50t+55t=70
50t+55t=105t=70
70/105
t=1.5
    
50t+55t=70
50t+55t=105t=70
70/105
t=1.5
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