Question

Victor left his house riding his bike at a speed of 18 km/hr. When Victor was 1/2 km from his house, his brother Alex left the house riding his bike towards Victor at a rate of 24 km/hr. How long will it take Alex to catch up with Victor?
how long for victor to go 1/2 km? call it cut ( catchuptime)
1/2 = 18 cut
cut = 1/36 hour
so if victor rides for time t +1/36
alex rides for t
d = 18(t+1/36) = 24 t
18 t+ 18/36 = 24 t
6 t = 1/2
t = 1/12 hour = 5 minutes
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I'm sorry, I do not understand what you are trying to say. Can you please provide more context or information?

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