Asked by Claudizzle

One car traveling at 55mi/h left a certai place 3h later than another car. The second car was traveling in the same direction at 40 mi/h. Inhow many hours ill the faster car ovrtae the other?

My work:

55(t-3) = 40t]
55t-165 = 40t
-55t -55t
-165 = -15t
/-15 /-15
11 = t
9 = t-3

I keep getting this answer, and my teacher told me it's worng, but I can't find what I'm doing wrong. Please HELP!!!
Answered by bobpursley
11-3=8, at least here in Texas.
Answered by Jose
13×+5×=3
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