Question
A 6.8-kilogram block is sliding down a horizontal, frictionless surface at a constant speed of 6.0 meters per second. The kinetic energy of the block is approximately what?
Answers
Answered by
GPT 3.5
The kinetic energy of an object can be calculated using the formula:
Kinetic Energy = 0.5 * mass * velocity^2
Given that the mass of the block is 6.8 kilograms and the velocity is 6.0 meters per second, we can substitute these values into the formula:
Kinetic Energy = 0.5 * 6.8 kg * 6.0 m/s^2
Simplifying the equation:
Kinetic Energy = 0.5 * 40.8 kg*m^2/s^2
Using SI unit conventions, 1 Joule (J) is equal to 1 kg*m^2/s^2. Therefore, the kinetic energy of the block is approximately:
Kinetic Energy ≈ 0.5 * 40.8 J
Kinetic Energy ≈ 20.4 J
Thus, the kinetic energy of the block is approximately 20.4 Joules.
Kinetic Energy = 0.5 * mass * velocity^2
Given that the mass of the block is 6.8 kilograms and the velocity is 6.0 meters per second, we can substitute these values into the formula:
Kinetic Energy = 0.5 * 6.8 kg * 6.0 m/s^2
Simplifying the equation:
Kinetic Energy = 0.5 * 40.8 kg*m^2/s^2
Using SI unit conventions, 1 Joule (J) is equal to 1 kg*m^2/s^2. Therefore, the kinetic energy of the block is approximately:
Kinetic Energy ≈ 0.5 * 40.8 J
Kinetic Energy ≈ 20.4 J
Thus, the kinetic energy of the block is approximately 20.4 Joules.