Asked by Anonymous
A 3.9-kilogram block sliding down a ramp from a height of 5.2 meters above the ground reaches the ground with a kinetic energy of 36 joules. The total work done by friction on the block as it slides down the ramp is approximately
Answers
Answered by
bobpursley
work done by gravity= frictionwork+KE
3.9g*5.2=36+frictionwork
3.9g*5.2=36+frictionwork
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