Asked by Adam

an adult 68 kg cheetah can accelerate from rest to 20.1 m/s (45 mph) in 2.0 s. Assuming constant acceleration, (a) find the net external force causing this acceleration. (b) where does the force come from? that is, what exerts the force on the cheetah?
Answered by bobpursley
a= deltav/time

F=ma

Doesn't the ground exert force on the cheta?
Answered by Adam
i don't get the first equation explain more please
Answered by bobpursley
acceleration= changeinvelocity/time.
Answered by Adam
should i be using the equation you wrote for finding the net EXTERNAL force??
Answered by bobpursley
Yes. That is the force accelerating the cheeta.
Answered by Adam
i got 1366.8 N and i'm asked to round to SF would it be 1.3*10^2?
Answered by bobpursley
a= 20.1m/s /2= 10.05m/s^2
F= ma

How did you get that number 1366?

Now, rounding 1366.8 is not 1/3E2

E2 is 100. But you have other errors that need to be corrected.

Answered by Adam
i corrected it and i got 683.4 N, does that sounds right? if yes, would it be 6.8E-1?
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