Asked by Sandhu
A ball is fired from a height of 3.0 m above the ground,with a speed of 13 m/s and an angle of 22 degrees below the horizontal.(a) At what time does the ball hit the ground? (b) What is the impact velocity?
Answers
Answered by
bobpursley
break the initial velocity into vertical and horiontal components.
Then use the vertical velocity in the distance equation..
3=Vvo*time - 4.9time^2 to solve for time.
Impact velocity will be the Vector sum of the initial vertical velocity and the final vertical velocity..
final velocityvertical=initialVv-g*t
Then use the vertical velocity in the distance equation..
3=Vvo*time - 4.9time^2 to solve for time.
Impact velocity will be the Vector sum of the initial vertical velocity and the final vertical velocity..
final velocityvertical=initialVv-g*t
Answered by
Sandhu
Thanks
Answered by
Nswabiseng
Mvi-mvf
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