Asked by yara

A ball is fired at a speed of 8 m/s at 20˚ above the horizontal from the top of a 5 m high wall. How far from the base of the ball will the ball hit the ground? Also calculate the angle below horizontal the velocity vector makes.

Answers

Answered by bobpursley
time in air:
hf=hi+vi*t-1/2 (9.8)t^2
0=5+8sin20*t-4.9t^2
solve that quadratic, use the quadratic equation.

Now, distance from base:
d=8Cos20*timeinair.

the angle: at impact?
arctan(verticalveloicty/horizontal)
verticalvelocity..
vf=8sin20-9.8t^2
so
angle arctan(vf/8cos20)
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions