Asked by Khalid
A bullet is fired with a speed of 450m/s through a board 20 cm thick. If the bullet is subject to a large deceleration of magnitude 106m/s2, will the bullet be able to emerge from the other side of the board ?
Answers
Answered by
drwls
The distance X required to stop the bullet when decelerating from Vo = 450 m/s at that rate (a) is given by
Vo = sqrt(2 a X), which can be rewritten
X = Vo^2/(2a)
It is not clear whether your deceleration rate is 106 m/s^2 or 10^6 m/s^2. It makes a difference in your answer.
Vo = sqrt(2 a X), which can be rewritten
X = Vo^2/(2a)
It is not clear whether your deceleration rate is 106 m/s^2 or 10^6 m/s^2. It makes a difference in your answer.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.