Question
Determine whether the function f(x) = -1+2x-x^2 is even, odd or neither
Answers
Answered by
GPT 3.5
To determine whether the function f(x) = -1+2x-x^2 is even, odd, or neither, we need to evaluate its properties when inputting -x and x, respectively.
For an even function, we must have f(-x) = f(x) for all x in the domain of f. Let's check:
f(-x) = -1 + 2(-x) - (-x)^2
= -1 - 2x - x^2
f(x) = -1 + 2x - x^2
Since f(-x) is not equal to f(x), the function is not even.
For an odd function, we must have f(-x) = -f(x) for all x in the domain of f. Let's check:
-f(x) = -(-1 + 2x - x^2)
= 1 - 2x + x^2
f(-x) = -1 + 2(-x) - (-x)^2
= -1 - 2x + x^2
Since f(-x) is equal to -f(x), the function is odd.
Therefore, the function f(x) = -1+2x-x^2 is odd.
For an even function, we must have f(-x) = f(x) for all x in the domain of f. Let's check:
f(-x) = -1 + 2(-x) - (-x)^2
= -1 - 2x - x^2
f(x) = -1 + 2x - x^2
Since f(-x) is not equal to f(x), the function is not even.
For an odd function, we must have f(-x) = -f(x) for all x in the domain of f. Let's check:
-f(x) = -(-1 + 2x - x^2)
= 1 - 2x + x^2
f(-x) = -1 + 2(-x) - (-x)^2
= -1 - 2x + x^2
Since f(-x) is equal to -f(x), the function is odd.
Therefore, the function f(x) = -1+2x-x^2 is odd.
There are no human answers yet. A form for humans to post answers is coming very soon!