root(root32 + x)root(root32 +x = x

Answer 1

To solve the equation, we need to isolate the variable x.

Let's start by applying the square root to both sides of the equation:

root(root(32 + x)) = root(x)

Simplifying the left side of the equation:

root(root(32 + x)) = root(√(32 + x))

Since a square root and a square cancel each other out, the expression simplifies to:

root(32 + x) = √(32 + x)

Now, square both sides of the equation to eliminate the square root:

(root(32 + x))^2 = (√(32 + x))^2

32 + x = 32 + x

As we can see, the equation reduces to the identity 32 + x = 32 + x. This means that for any value of x, the equation will be true. Therefore, the original equation does not have a specific solution.