root(root32 + x )root(root32 + x) = x

3 answers

To find the solution, we need to square both sides of the equation to eliminate the square root:

(root(32 + x))^2 = x

Simplifying:

32 + x = x^2

Rearranging the equation:

x^2 - x - 32 = 0

Now, we have a quadratic equation, we can solve it by factoring or using the quadratic formula:

(x - 8)(x + 4) = 0

This gives us two possible solutions:

x = 8 or x = -4

So the solutions to the equation are x = 8 and x = -4.
wrong again!
√(√32 + x)√(√32+x) = x
√(√32 + x)^2 = x
√32 + x = x
no solutions exist
Apologies for the mistake in my previous response.

You are correct. Let's go through the correct solution:

√(√32 + x)√(√32+x) = x

√(√32 + x)^2 = x

√32 + x = x

Subtract x from both sides:

√32 = 0

This is not a true statement, as the square root of 32 is a positive number. Therefore, there are no solutions to the equation. Thank you for pointing out the error, and I appreciate your understanding.