Question
A Ferris wheel 28.0m in diameter rotates once every 21.0s.
What is the ratio of a person's apparent weight to her real weight at the top?
What is the ratio of a person's apparent weight to her real weight at the bottom?
What is the ratio of a person's apparent weight to her real weight at the top?
What is the ratio of a person's apparent weight to her real weight at the bottom?
Answers
radius, r = 28/2 m =14 m
Period, T = 21 s
angular velocity, ω = 2π/21 rad/s
Centrifugal force, f= mrω²
actual weight, w = mg
apparent weight at top, wt = mg -f
apparent weight at bottom, wb = mg+f
Solve for f and calculate wt/w and wb/w.
Period, T = 21 s
angular velocity, ω = 2π/21 rad/s
Centrifugal force, f= mrω²
actual weight, w = mg
apparent weight at top, wt = mg -f
apparent weight at bottom, wb = mg+f
Solve for f and calculate wt/w and wb/w.
so i have a question how do you solve for f if there is no m?
the m's cancel at some point in the equation
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