Question
A car travels on a straight, level road.
(a) Starting from rest, the car is going 34 ft/s (23 mi/h) at the end of 5.5 s. What is the car's average acceleration in ft/s2?
(a) Starting from rest, the car is going 34 ft/s (23 mi/h) at the end of 5.5 s. What is the car's average acceleration in ft/s2?
Answers
GPT 3.5
To find the average acceleration, we can use the formula:
average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 ft/s (since the car starts from rest)
Final velocity (v) = 34 ft/s
Time (t) = 5.5 s
Plugging in these values into the formula, we get:
average acceleration = (34 ft/s - 0 ft/s) / 5.5 s
average acceleration = 34 ft/s / 5.5 s
average acceleration ≈ 6.182 ft/s²
Therefore, the car's average acceleration is approximately 6.182 ft/s².
average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 ft/s (since the car starts from rest)
Final velocity (v) = 34 ft/s
Time (t) = 5.5 s
Plugging in these values into the formula, we get:
average acceleration = (34 ft/s - 0 ft/s) / 5.5 s
average acceleration = 34 ft/s / 5.5 s
average acceleration ≈ 6.182 ft/s²
Therefore, the car's average acceleration is approximately 6.182 ft/s².
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