Asked by Jessica
A car travels along a straight road, heading east for 1 h, then traveling for 30 min on another road that leads northeast. If the car has maintained a constant speed of 48 mi/h, how far is it from its starting position? Round your answer to 2 decimal places.
Answers
Answered by
Henry
d1 = 45m/h * 1h = 45mi @ 0 deg.
d2 = 45m/h * 0.5h = 22.5mi @ 45deg.
X = hor. = 45 + 22.5cos45 = 60.91mi.
Y = ver. = 22.5sin45 = 15.91mi.
d^2 = X^2 + Y^2,
d^2 = (60.91)^2 + (15.91)^2 = 3963.16,
d = 62.95mi.
d2 = 45m/h * 0.5h = 22.5mi @ 45deg.
X = hor. = 45 + 22.5cos45 = 60.91mi.
Y = ver. = 22.5sin45 = 15.91mi.
d^2 = X^2 + Y^2,
d^2 = (60.91)^2 + (15.91)^2 = 3963.16,
d = 62.95mi.
Answered by
Brandi Williams
The mph is suppose to be 48
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