Asked by Mo
A football is kicked at ground level with a speed of 20.8m/s at an angle of 23.3 degress to the horizontal. How much later, in seconds, does it hit the ground?
Tf =(-20.8m/s x Sin 23.3)/-9.80m/s^2
=0.839s
this doesn't sound right to me
Tf =(-20.8m/s x Sin 23.3)/-9.80m/s^2
=0.839s
this doesn't sound right to me
Answers
Answered by
bobpursley
h(t)=h(0)+vvt-1/2 g t^2
0=0+20.8sin23.3 t - 4.9t^2
t=0, t=20.8sin23.3/4.9
so your denominator is wrong.
0=0+20.8sin23.3 t - 4.9t^2
t=0, t=20.8sin23.3/4.9
so your denominator is wrong.
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