Asked by Jacob
                A football is kicked at ground level with a speed of 17.7 m/s at an angle of 39.8 ∘ to the horizontal.
How much later does it hit the ground?
Answer=> t=_____ s
Express your answer using three significant figures and include the appropriate units.
            
        How much later does it hit the ground?
Answer=> t=_____ s
Express your answer using three significant figures and include the appropriate units.
Answers
                    Answered by
            Henry
            
    Vo = 17.7 m/s[39.8o].
Yo = 17.7*sin(39.8) = 11.33 m/s. = Vert. component of Vo.
Y = Yo + g*Tr = 0.
11.33 - 9.8Tr = 0, Tr = 1.16 s. = Rise time.
T = Tr+Tf. Tf = Tr.
T = Tr+Tr = 1.16 + 1.16 = 2.32 s.
 
    
Yo = 17.7*sin(39.8) = 11.33 m/s. = Vert. component of Vo.
Y = Yo + g*Tr = 0.
11.33 - 9.8Tr = 0, Tr = 1.16 s. = Rise time.
T = Tr+Tf. Tf = Tr.
T = Tr+Tr = 1.16 + 1.16 = 2.32 s.
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