Asked by Lee
the radius of a curvature is 10ft and the height of the segment is 2ft. What is the length of the chord
Answers
Answered by
MathMate
Let the length of the chord be x.
Draw a perpendicular bisector to the chord and let it intersect the circles at A and B. The mid-point of the chord is M.
Since the radius is 10 ft, the diameter is 20 ft. mAM=2 ft, and mMB = 20-2=18 ft.
By the property of intersecting chords,
(x/2)² = mAM . mMB
=2*18
=36
x/2=6 ft
x= 12 ft.
Draw a perpendicular bisector to the chord and let it intersect the circles at A and B. The mid-point of the chord is M.
Since the radius is 10 ft, the diameter is 20 ft. mAM=2 ft, and mMB = 20-2=18 ft.
By the property of intersecting chords,
(x/2)² = mAM . mMB
=2*18
=36
x/2=6 ft
x= 12 ft.
There are no AI answers yet. The ability to request AI answers is coming soon!