I am unsure how to factor x^3-8. Could you please explain?

3 answers

x^3-8
This is a standard case of the form
(x³-y³)
=(x-y)(x²+xy+y²)
Can you take it from here?
x^3+-448x?
x³-8
=x³-2³
if you put x=x, and y=2 in the above identity, you will have factorized the expression as the product of a binomial and a trinomial.