Question

Dissolve 0.1gm of cane sugar in 2cc if water. To this dilute solution in a test tube, add 2 drops of molischs reagent and shake. Carefully pour 2cc o conc H2SO4 down the side of the tube and allow to stand for 2 minutes
State your observations

Answer 1

Based on the given instructions, the following observations can be made:

1. Upon dissolving 0.1gm of cane sugar in 2cc of water, the sugar should completely dissolve, resulting in a clear and colorless solution.

2. After adding 2 drops of Molisch's reagent to the solution and shaking it, there may be a color change or formation of a colored ring at the junction between the two liquids. Molisch's reagent is typically used to detect the presence of carbohydrates, and if sugar is present, it can lead to the formation of a purple or violet ring.

3. Carefully pouring 2cc of concentrated H2SO4 down the side of the test tube, there may be a heat release or evolution of gases. Sulfuric acid is a strong dehydrating agent, and when mixed with sugar, it can cause a reaction known as caramelization or charring. This could lead to the coloration of the solution, production of odorous fumes, or possible darkening or blackening of the solution.

4. After allowing the mixture to stand for 2 minutes, there may be further changes in the appearance of the solution. The intense acidic conditions and the heat generated earlier may have caused additional chemical reactions, such as degradation or further darkening of the solution.

Overall, the observations may include the initial dissolution of sugar in water, the formation of a colored ring upon addition of Molisch's reagent, possible heat release and gas evolution during the addition of H2SO4, and a visual change in the appearance of the solution after the reaction is allowed to stand.