Question
I'm trying to solve the problem: 6y-bracket 3y-(y+7)bracket. I got an answer of 4y-7 multiple times. However, my book said the answer is 4y+7. I do not see how the 7 can be positive. I distributed the negative, so therefore, the seven should be negative. Or are parenthesis within brackets exempt from negative signs outside the brackets? Thanks for your help?
Answers
you do whats in the brackets first
like 3y-(y+7)
you take out the parenthesis and then you subtract 3y-y+7=2y+7
now you have 6y-[2y+7]
now you take the brackets away
6y-2y+7=4y+7
like 3y-(y+7)
you take out the parenthesis and then you subtract 3y-y+7=2y+7
now you have 6y-[2y+7]
now you take the brackets away
6y-2y+7=4y+7
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