Asked by Anonymous
A vector has an x component of -30.0 units and a y component of 49.5 units. Find the magnitude and direction of the vector.
Answers
Answered by
MathMate
With the number of questions on vectors you have asked lately, you would certainly be able to work out part of the question, or else you will have a problem at exam time.
Here is how you can do it. If you have difficulties, post what you get.
Vector(-30, 49.5)
Magnitude=√(x²+y²)
=√((-30)²+49.5²)
=?
The direction is a little more tricky, as you will have to determine which quadrant the vector belongs.
Since x<0 and y>0, we determine that it is in the second quadrant.
Find θ=tan<sup>-1</sup>(49.5/30) and subtract from 180° (2nd quadrant) to get the direction of the vector.
Here is how you can do it. If you have difficulties, post what you get.
Vector(-30, 49.5)
Magnitude=√(x²+y²)
=√((-30)²+49.5²)
=?
The direction is a little more tricky, as you will have to determine which quadrant the vector belongs.
Since x<0 and y>0, we determine that it is in the second quadrant.
Find θ=tan<sup>-1</sup>(49.5/30) and subtract from 180° (2nd quadrant) to get the direction of the vector.