With the number of questions on vectors you have asked lately, you would certainly be able to work out part of the question, or else you will have a problem at exam time.
Here is how you can do it. If you have difficulties, post what you get.
Vector(-30, 49.5)
Magnitude=√(x²+y²)
=√((-30)²+49.5²)
=?
The direction is a little more tricky, as you will have to determine which quadrant the vector belongs.
Since x<0 and y>0, we determine that it is in the second quadrant.
Find θ=tan-1(49.5/30) and subtract from 180° (2nd quadrant) to get the direction of the vector.
A vector has an x component of -30.0 units and a y component of 49.5 units. Find the magnitude and direction of the vector.
1 answer