Asked by Mallory
The x-component of vector A is -25.0 m and the y-component is +40.0 m.
a) what is the magnitude of vector A?
b) What is the angle between the direction of vector A and the positive direction of vector x?
can you please help me with the steps to accomplishing these?
a) what is the magnitude of vector A?
b) What is the angle between the direction of vector A and the positive direction of vector x?
can you please help me with the steps to accomplishing these?
Answers
Answered by
MathMate
The magnitude is obtained by taking the square root of the sum of squares of the components.
A vector with 3 and 4 units as the x- and y-components will have a magnitude of √(3²+4²)=5 units.
The angle of the vector measured from the x-axis is given by tan<sup>-1</sup>(y-component/x-component).
Be careful with the quadrant, as the tan<sup>-1</sup> function usually ranges only from -π/2 to π/2.
A vector with 3 and 4 units as the x- and y-components will have a magnitude of √(3²+4²)=5 units.
The angle of the vector measured from the x-axis is given by tan<sup>-1</sup>(y-component/x-component).
Be careful with the quadrant, as the tan<sup>-1</sup> function usually ranges only from -π/2 to π/2.
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