substitute m from the second equation into the first to give:
k² + k(k-6) = 8
k² + k² - 6k = 8
2k² -6k -8 =0
k² -3k -4 = 0
(k-4)(k+1)=0
k=4 or k=-1
Substitute each value of k into the second equation to give:
m=k-6
=4-6
=-2
or
m=k-6
=-1-6
=-7
Solve
k^2 + km = 8
m = k- 6
Can you show me step-by step please?
1 answer