A helicopter is ascending vertically with a speed of 4.00 m/s. At a height of 185 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?

Answer 1

The initial velocity of the package is also the velocity of the helicopter, 4.00m/s.

The displacement required to reach the ground is 185m.

Acceleration is due to gravity.

Now use the equation d = Vi * t + (1/2)*a*t^2 to find time.

-185m = 4.00m/s * t - (1/2)* g * t^2

You will need to use the Quadratic formula.

Note how the signs are placed - positive is upwards, negative is downwards.