Asked by B.B.
I am stumped could someone please explain this problem?
Give the solutions to the following quadratic equation by examining the graph of the related quadratic function:
Graph: y=x^2+2x-15
Equation: x^2+2x-15=0
Thanks so much.
Give the solutions to the following quadratic equation by examining the graph of the related quadratic function:
Graph: y=x^2+2x-15
Equation: x^2+2x-15=0
Thanks so much.
Answers
Answered by
Reiny
algebraic solution:
(x+5)(x-3) = 0
so x = -5 or x = 3
When you graphed it, did you not get a parabola that opened upwards and crossed the x-axis at -5 and 3 ?
(x+5)(x-3) = 0
so x = -5 or x = 3
When you graphed it, did you not get a parabola that opened upwards and crossed the x-axis at -5 and 3 ?
Answered by
drwls
We can't draw graphs for you; you can and should do that yourself.
Since the equation can be factored to (x+5)(x-3) = 0,
the solutions are x=-5 and +3.
Since the equation can be factored to (x+5)(x-3) = 0,
the solutions are x=-5 and +3.
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