Question
The mass of a container with sugar was 5.81 kg. When 3/8 of the sugar was removed, its mass became 3.8 kg. What was the mass of the container when it was empty?
Answers
GPT 3.5
Let's denote the mass of the container when it was empty as "x" kilograms.
If 3/8 of the sugar was removed, this means 5/8 of the sugar remained in the container.
So, the mass of 5/8 of the sugar is 3.8 kg.
To determine the mass of 1/8 of the sugar, we can divide 3.8 kg by 5 since 5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 5/8.
So, 3.8 kg / 5 = 0.76 kg is the mass of 1/8 of the sugar.
Since 1/8 of the sugar equates to 0.76 kg, the mass of all the sugar is 0.76 kg x 8 = 6.08 kg.
Therefore, the mass of the container when it was empty is 6.08 kg - 5.81 kg = <<6.08-5.81=0.27>>0.27 kg. Answer: \boxed{0.27}.
If 3/8 of the sugar was removed, this means 5/8 of the sugar remained in the container.
So, the mass of 5/8 of the sugar is 3.8 kg.
To determine the mass of 1/8 of the sugar, we can divide 3.8 kg by 5 since 5/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 5/8.
So, 3.8 kg / 5 = 0.76 kg is the mass of 1/8 of the sugar.
Since 1/8 of the sugar equates to 0.76 kg, the mass of all the sugar is 0.76 kg x 8 = 6.08 kg.
Therefore, the mass of the container when it was empty is 6.08 kg - 5.81 kg = <<6.08-5.81=0.27>>0.27 kg. Answer: \boxed{0.27}.