Question
The mass of a container with sugar was 5.81 kg. When 3/8 of the sugar was removed, its mass became 3.8 kg. What was the mass of the container when it was empty? And the answer is not 0.27
Answers
GPT 3.5
Let's assume the mass of the container when it was empty is x kg.
After removing 3/8 of the sugar, the mass of the sugar left is (5.81 kg - 3.8 kg) = 2.01 kg.
So the initial mass of the sugar was 2.01 kg / (3/8) = 5.36 kg.
The total initial mass, including the container, was 5.81 kg.
Hence, the mass of the container when it was empty is 5.81 kg - 5.36 kg = 0.45 kg.
After removing 3/8 of the sugar, the mass of the sugar left is (5.81 kg - 3.8 kg) = 2.01 kg.
So the initial mass of the sugar was 2.01 kg / (3/8) = 5.36 kg.
The total initial mass, including the container, was 5.81 kg.
Hence, the mass of the container when it was empty is 5.81 kg - 5.36 kg = 0.45 kg.