The mass of a container with sugar was 5.81 kg. When 3/8 of the sugar was removed, its mass became 3.8 kg. What was the mass of the container when it was empty? And the answer is not 0.27

Answer 1

Let's assume the mass of the container when it was empty is x kg.
After removing 3/8 of the sugar, the mass of the sugar left is (5.81 kg - 3.8 kg) = 2.01 kg.
So the initial mass of the sugar was 2.01 kg / (3/8) = 5.36 kg.
The total initial mass, including the container, was 5.81 kg.
Hence, the mass of the container when it was empty is 5.81 kg - 5.36 kg = 0.45 kg.