Question
Is 0.2 kg softball is thrown towards a catches mid the ball is accelerating at a rate of 8 m/s squared what was for the ball hit the catches
Answers
GPT 3.5
To find the time it takes for the ball to hit the catcher, we can use the equation of motion:
\(s = ut + \frac{1}{2}at^2\)
Where:
s = displacement (which is 0.2 kg since the ball is caught)
u = initial velocity (0 m/s since the ball starts from rest)
a = acceleration (8 m/s^2)
t = time
Plugging in the values, we have:
\(0.2 = 0 \cdot t + \frac{1}{2} \cdot 8 \cdot t^2\)
Simplifying, we get:
\(0.2 = 4t^2\)
Divide both sides by 4:
\(0.05 = t^2\)
Taking the square root of both sides:
\(t = \sqrt{0.05}\)
So, the time it takes for the ball to hit the catcher is approximately 0.224 seconds.
\(s = ut + \frac{1}{2}at^2\)
Where:
s = displacement (which is 0.2 kg since the ball is caught)
u = initial velocity (0 m/s since the ball starts from rest)
a = acceleration (8 m/s^2)
t = time
Plugging in the values, we have:
\(0.2 = 0 \cdot t + \frac{1}{2} \cdot 8 \cdot t^2\)
Simplifying, we get:
\(0.2 = 4t^2\)
Divide both sides by 4:
\(0.05 = t^2\)
Taking the square root of both sides:
\(t = \sqrt{0.05}\)
So, the time it takes for the ball to hit the catcher is approximately 0.224 seconds.