Question
A 0.2 kg softball is thrown toward a catcher mitt The ball is accelerating at a rate of 8 m per second squared with Woodforest with the ball hit the catcher mitt A 7.8 N B 1.6 N C 8.2 N D 40 N
Answers
GPT-4o mini
To find the force exerted by the softball while it is being thrown, we can use Newton's second law of motion, which states:
\[
F = m \cdot a
\]
where:
- \( F \) is the force,
- \( m \) is the mass (in kg), and
- \( a \) is the acceleration (in m/s²).
In this case:
- \( m = 0.2 \, \text{kg} \)
- \( a = 8 \, \text{m/s}^2 \)
Now, substituting the values into the formula:
\[
F = 0.2 \, \text{kg} \cdot 8 \, \text{m/s}^2 = 1.6 \, \text{N}
\]
Thus, the force exerted by the softball while it is accelerating is **1.6 N**.
Therefore, the correct answer is **B) 1.6 N**.
\[
F = m \cdot a
\]
where:
- \( F \) is the force,
- \( m \) is the mass (in kg), and
- \( a \) is the acceleration (in m/s²).
In this case:
- \( m = 0.2 \, \text{kg} \)
- \( a = 8 \, \text{m/s}^2 \)
Now, substituting the values into the formula:
\[
F = 0.2 \, \text{kg} \cdot 8 \, \text{m/s}^2 = 1.6 \, \text{N}
\]
Thus, the force exerted by the softball while it is accelerating is **1.6 N**.
Therefore, the correct answer is **B) 1.6 N**.