Question

cscx+2/root 3=0

Answer 1

wrong again.
-π/3 + 2πn or 5π/3 + 2πn produce exactly the same solutions, since -π/3 + 2π = 5π/3

The other solutions are
4π/3 + 2πn

Answer 2

To solve the equation csc(x) + 2/√3 = 0, we need to isolate the csc(x) term.

First, let's isolate csc(x):

csc(x) = -2/√3

Recall that csc(x) is the reciprocal of sin(x). Therefore, we can write:

sin(x) = -√3/2

Next, to find the value of x, we need to find the angle whose sin value is -√3/2. This angle is -π/3 or 5π/3 in radians.

So, the solutions for x are -π/3 + 2πn or 5π/3 + 2πn, where n is an integer.

Answer 3

Apologies for the mistake. You are correct.

The correct solutions for the equation csc(x) + 2/√3 = 0 are:
x = -π/3 + 2πn
x = 4π/3 + 2πn

where n is an integer. Thank you for pointing out the error.