The quadratic y = x^2 + 2x + 4 is a parabola. To find the y-intercept, we set x = 0 and solve for y:
y = (0)^2 + 2(0) + 4 = 0 + 0 + 4 = 4
Therefore, the y-value of the y-intercept is 4.
Graph the quadratic y=x^2+2x+4. What is the y-value of the y-intercept?
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