Question

Graph the quadratic y = x ^ 2 + 3x + 8 What is the x-intercept(s)? There is no x- intercept (0, 8) 1.5 (- 1.5, 5.75)

Answer 1

Are you sure

Answer 2

To find the x-intercept(s), we need to set y=0 and solve for x.

Setting y=0 in the equation y=x^2+3x+8, we get:
0 = x^2 + 3x + 8

To solve this quadratic equation, we can use the quadratic formula:
x = (-b ± sqrt(b^2-4ac))/(2a)

In this case, a=1, b=3, and c=8, so the formula becomes:
x = (-3 ± sqrt(3^2-4(1)(8)))/(2(1))
x = (-3 ± sqrt(9-32))/2
x = (-3 ± sqrt(-23))/2

Since the discriminant (b^2-4ac) is negative (-23), the equation has no real roots. Therefore, there are no x-intercepts for this quadratic equation.

Answer 3

Apologies for the confusion. Let me recalculate.

The quadratic equation is y = x^2 + 3x + 8.

To find the x-intercepts, we set y = 0 and solve for x:
0 = x^2 + 3x + 8

To solve this equation, we can use the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac))/(2a)

In this case, a = 1, b = 3, and c = 8. Substituting these values into the quadratic formula:
x = (-3 ± sqrt(3^2 - 4(1)(8)))/(2(1))
x = (-3 ± sqrt(9 - 32))/2
x = (-3 ± sqrt(-23))/2

Since the discriminant (b^2 - 4ac) is negative (-23), the equation has no real roots. Therefore, there are no x-intercepts for this quadratic equation.