Question

Suppose the position of an object is given by ->r(vector) = (3.0t^2*ihat - 6.0t^3*jhat)m. Where t in seconds.

Determine its velocity ->v as a function of time t.

Determine its acceleration ->a as a function of time t.


Determine ->r at time t = 2.5 s.

Determine ->v at time t = 2.5s

Answer 1

velocity is the first derivative of position.

v=6.0t i -18.0 t^2 j
acceleration is the second derivative of position or
a= 6.0 i -36 t j

Answer 2

suppose the position of an object is given by r = (3.0 t^2-i - 6.0t^3 j)m.(a) determine its velocity v and acceleration a, as a function of time. (b) determine r and v at time t = 2.5 s.