Asked by Andrea

Suppose that the position y (feet) of a projectile above the ground is described by the equation y=-16t^2+70t+2, where t is the time elapsed (seconds) since the object was launched. (A) What is the initial position of the object? (B) When will the object strike the ground? Please help!!!! :(

Answers

Answered by scott
(A) when t=0 , y = 2

(B) the ground is y=0
... 0 = -16t^2 + 70t + 2 ... solve the quadratic for t to find the impact time
... use the quadratic formula
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