since 832 >= 400, 832/400 > 1, and the 1st digit is in the hundreds position
217 < 700, but 217 >= 70, so 1st digit of quotient is in the tens position.
1. 832/4
2. 217/7
I don't understand. Someone please explain to me.
217 < 700, but 217 >= 70, so 1st digit of quotient is in the tens position.
1. For 832/4:
Divide 832 by 4:
- Start with the leftmost digit of the dividend (8).
- Determine how many times the divisor (4) can go into the first digit without exceeding it.
In this case, 4 can go into 8 exactly 2 times. So, the first digit of the quotient is 2.
Therefore, the position of the first digit of the quotient in 832/4 is at the ones place.
2. For 217/7:
Divide 217 by 7:
- Start with the leftmost digit of the dividend (2).
- Determine how many times the divisor (7) can go into the first digit without exceeding it.
In this case, 7 cannot go into 2 at all because 2 is smaller than 7.
In such cases, the first digit of the quotient is a 0 or remains empty.
Therefore, the position of the first digit of the quotient in 217/7 is at the tens place.
In summary, the first digit of the quotient can be found by dividing the first digit of the dividend by the divisor and considering the position of the digit in the quotient.