Question
I am getting difficulties by doin this homework.plzzzz can u hel pme;Solve this simultaneous equation;1/3(x+2)-1/4(y-1)=1,5X=4Y(B)SOLVE TO 2 DECIMAL PLACES'x-15/x=12.
The second number am not sure of my calcalations;The point (x,y)is transformed by the matrix (5 -1) TO(19 9) (2 1)
FIND THE VALUE OF X AND Y. n I GOT 4 N 1 AS THE ANSWER...
The second number am not sure of my calcalations;The point (x,y)is transformed by the matrix (5 -1) TO(19 9) (2 1)
FIND THE VALUE OF X AND Y. n I GOT 4 N 1 AS THE ANSWER...
Answers
multiply your first equation by 12 to get
4(x+2)-3(y-1)=12
4x-3y=1 call this equation #1
take your orignal second equation, multiply it by 4 and take all terms to the left side
20x-16y=0 call this equation #2
#1 times 5 ---> 20x-15y=5
#2 ----------> 20x-16y=0 subtract them to get
y=5
back in #2 ----> 20x-75=5
20x=80
x=4
I don't understand your second question
4(x+2)-3(y-1)=12
4x-3y=1 call this equation #1
take your orignal second equation, multiply it by 4 and take all terms to the left side
20x-16y=0 call this equation #2
#1 times 5 ---> 20x-15y=5
#2 ----------> 20x-16y=0 subtract them to get
y=5
back in #2 ----> 20x-75=5
20x=80
x=4
I don't understand your second question