Asked by Laura
if 5.00g magnesium is combined with 10.0 g of chlorine, show by calculation which substance is the limiting reactant and calculate the theoretical yield of magnesium chloride for the reaction. Someone PLEASE HELP ME!!!!
Answers
Answered by
pop
Mg + Cl2 -> MgCl2
5.00 g Mg / 24 g/mol / 1 (from balanced equation) = 0.21
10.0 g Cl2 / 71 g/mol / 2 (from balanced equation) = 0.070
Smallest number is limiting reactant = Cl2
Yield = 10.0 g Cl2 / 71g/mol X 1 mol MgCl2/1 mol Cl2 X 95 g MgCl2/mol = 13.4 g
5.00 g Mg / 24 g/mol / 1 (from balanced equation) = 0.21
10.0 g Cl2 / 71 g/mol / 2 (from balanced equation) = 0.070
Smallest number is limiting reactant = Cl2
Yield = 10.0 g Cl2 / 71g/mol X 1 mol MgCl2/1 mol Cl2 X 95 g MgCl2/mol = 13.4 g
Answered by
pop
10 g Cl2 / 71 g/mol /1 (balanced equation) = 0.141
Still the limiting reactant\
MgCl2 is still 13.4
Sorry!
Still the limiting reactant\
MgCl2 is still 13.4
Sorry!
Answered by
Mustapha
On what
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