If the pH of a solution NaCN is 8.710 the equilibrium concentration of CN^- is

1 answer

To determine the equilibrium concentration of CN^- in a solution of NaCN, we need to use the pH value and the dissociation constant of NaCN.

The pH of a solution is a measure of the concentration of H+ ions in the solution. In this case, we know that the pH of the solution is 8.710.

To find the equilibrium concentration of CN^-, we can use the pOH value, which is the negative logarithm of the concentration of OH- ions in the solution. Since water is the only source of OH- ions in this case, we can find the pOH value using the following equation:

pOH = 14 - pH

pOH = 14 - 8.710 = 5.29

To find the equilibrium concentration of CN^-, we can use the dissociation constant of NaCN. The dissociation constant (Ka) is a value that indicates the extent to which a compound dissociates in a solution. In this case, the dissociation constant (Ka) of NaCN is not provided, so we cannot calculate the equilibrium concentration of CN^- without this information.

However, if we assume that NaCN completely dissociates in water, we can say that the equilibrium concentration of CN^- is equal to the concentration of NaCN. Since we do not have the concentration of NaCN, we cannot determine the equilibrium concentration of CN^- in this specific scenario.