Asked by muffy
Does this:
sqrt 3x-4=(x-4)^2-3
Multiply out to:
x^4-16x^3+90x^2-111x+173
Once I know it is multiplied out right then I can continue. Thanks
sqrt 3x-4=(x-4)^2-3
Multiply out to:
x^4-16x^3+90x^2-111x+173
Once I know it is multiplied out right then I can continue. Thanks
Answers
Answered by
Steph
i got 3x^2-16x+16
Answered by
Reiny
no
first of all, you don't have an equation as your answer.
√(3x-4)=(x-4)^2-3
square both sides
3x-4 = (x-4)^4 - 6(x-4)^2 + 9
3x - 4 = x^4 - 16x^3 + 96x^2 - 256x + 256 - 6x^2 + 48x - 96 + 9
x^4 - 16x^3 + 102x^2 - 211x + 166 = 0
first of all, you don't have an equation as your answer.
√(3x-4)=(x-4)^2-3
square both sides
3x-4 = (x-4)^4 - 6(x-4)^2 + 9
3x - 4 = x^4 - 16x^3 + 96x^2 - 256x + 256 - 6x^2 + 48x - 96 + 9
x^4 - 16x^3 + 102x^2 - 211x + 166 = 0
Answered by
muffy
Oh thanks didn't see this post.
I realized I needed to make it equal zero. I keep getting 90 x^2 instead of 102 and 173 instead of 166.
Why do they make this so hard?
I realized I needed to make it equal zero. I keep getting 90 x^2 instead of 102 and 173 instead of 166.
Why do they make this so hard?
Answered by
Reiny
the difficulty is that you have to square the whole side, not just each term.
I agree with you, that is a hard question at your level.
Solving the final equation would be a nightmare.
I agree with you, that is a hard question at your level.
Solving the final equation would be a nightmare.
Answered by
muffy
I'm looking at your solution and I can't figure out where that -6 came from.