Asked by muffy
                Does this:
sqrt 3x-4=(x-4)^2-3
Multiply out to:
x^4-16x^3+90x^2-111x+173
Once I know it is multiplied out right then I can continue. Thanks
 
            
            
        sqrt 3x-4=(x-4)^2-3
Multiply out to:
x^4-16x^3+90x^2-111x+173
Once I know it is multiplied out right then I can continue. Thanks
Answers
                    Answered by
            Steph
            
    i got 3x^2-16x+16
    
                    Answered by
            Reiny
            
    no
first of all, you don't have an equation as your answer.
√(3x-4)=(x-4)^2-3
square both sides
3x-4 = (x-4)^4 - 6(x-4)^2 + 9
3x - 4 = x^4 - 16x^3 + 96x^2 - 256x + 256 - 6x^2 + 48x - 96 + 9
x^4 - 16x^3 + 102x^2 - 211x + 166 = 0
    
first of all, you don't have an equation as your answer.
√(3x-4)=(x-4)^2-3
square both sides
3x-4 = (x-4)^4 - 6(x-4)^2 + 9
3x - 4 = x^4 - 16x^3 + 96x^2 - 256x + 256 - 6x^2 + 48x - 96 + 9
x^4 - 16x^3 + 102x^2 - 211x + 166 = 0
                    Answered by
            muffy
            
    Oh thanks didn't see this post.
I realized I needed to make it equal zero. I keep getting 90 x^2 instead of 102 and 173 instead of 166.
Why do they make this so hard?
    
I realized I needed to make it equal zero. I keep getting 90 x^2 instead of 102 and 173 instead of 166.
Why do they make this so hard?
                    Answered by
            Reiny
            
    the difficulty is that you have to square the whole side, not just each term.
I agree with you, that is a hard question at your level.
Solving the final equation would be a nightmare.
    
I agree with you, that is a hard question at your level.
Solving the final equation would be a nightmare.
                    Answered by
            muffy
            
    I'm looking at your solution and I can't figure out where that -6 came from.
    
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